8m^2/3m=8

Solution for 8m^2/3m=8 equation:

8m^2/3m=8

We move all terms to the left:

8m^2/3m-(8)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R


We multiply all the terms by the denominator


8m^2-8*3m=0

Wy multiply elements

8m^2-24m=0

a = 8; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·8·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*8}=\frac{0}{16}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*8}=\frac{48}{16}
=3
$